During normal beating, a heart creates a maximum 3.8-mV potential across 0.32 m

Question

During normal beating, a heart creates a maximum 3.8-mV potential across 0.32 m of a person’s chest, creating a 0.85-Hz electromagnetic wave. During normal beating of the heart, the maximum value of the oscillating potential difference across 0.32 m of a person’s chest is 3.8 mV. This oscillating potential difference produces a 0.85-Hz electromagnetic wave.

a)What is the maximum electric field strength, in volts per meter, of the electromagnetic wave?

b)What is the corresponding maximum magnetic field strength, in teslas, of the electromagnetic wave?

c)What is the wavelength, in meters, of the electromagnetic wave?

Explanation / Answer

(A) Em = Vmax / d

= (3.8 x 10^-3 V) / (0.32 m)

= 0.011875 V/m Or 11.9 x 10^-3 V/m

(B) Bm = Em / c

= (11.9 x 10^-3) / (3 x 10^8)

= 3.958 x 10^-11 T

(C) lambda = c / f

= (3 x 10^8) / (0.85)

= 3.53 x 10^8 m

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