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WE DID NOT NEED TO GET THE DIAGRAM. THERE IS NO DIAGRAM QUESTIONS: the cart is g

ID: 1552310 • Letter: W

Question

WE DID NOT NEED TO GET THE DIAGRAM.

THERE IS NO DIAGRAM

QUESTIONS: the cart is given by 1. Prove that the equation of momentum change for where M is the mass of the cart (with bar mass), Ax2 x2 -xo, Axi xo, and e is the angle of the inclined plane. 2. What experimental errors are significant for this experiment? 3. If the initial height of ball is 1.80 m, a ball of mass 0.22 kg is dropped from rest. It rebounds back from the floor to a height of 1.50 m. Determine the impulse on the ball delivered by the floor.

Explanation / Answer

Rebound height = 1.5 m

v = sqrt(2*9.8*1.5) = 5.42 m/s upwards

Now during the fall v = sqrt(2*9.8*1.8) = 5.939m/s

So Change in momentum = Impulse = 0.22* (5.939 +5.42) = 2.498