Two containers have a substantial amount of the air evacuated out of them so tha

Question

Two containers have a substantial amount of the air evacuated out of them so that the pressure inside is half the pressure at sea level. One container is in Denver at an altitude of about 6,000 ft and the other is in New Orleans (at sea level). The surface area of the container lid is A = 0.0155 m^2. The air pressure in Denver is P_D = 80500 Pa. and in New Orleans is P _NO = 101250 Pa. Assume the lid is weightless. Write an expression for the force F_NO required to remove the container lid in New Orleans. F_NO = Calculate the force F_NO required to lift off the container lid in New Orleans in N. Calculate the force F_D required to lift off the container lid in Denver in N.

Explanation / Answer

Given that

atmospheric pressure in denver PD = 80500 Pa

atmospheric pressure in new orleans PNO = 101250 Pa

surface area of lid A = 0.0155 m^2

Pressure inside the container,

PC = Psea / 2 = PNO / 2

PC = 101250 / 2 = 50625 Pa

(a)

Force required to open the lid is,

F = (Patm - PC)*A

Force required to open the lid in new orleans,

FNO = (PNO - PC)*A = (101250 - 50625)*0.0155

FNO = 784.6875 N

(c)

FD = (PD - PC)*A = (80500 - 50625)*0.0155

FD = 463.0625 N

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