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can you help me understand this question: A 50-kg block rests on a horizontal su

ID: 1552139 • Letter: C

Question

can you help me understand this question:

A 50-kg block rests on a horizontal surface. The coefficient of static friction µs = 0.50. The coefficient of kinetic friction µk = 0.35. A force P of 240 N is applied.

A) The block remains at rest. B) The block moves and continues to move at constant velocity. C) The block accelerates to the right. D) The block does not move until P is increased to greater than 490 N. E) No conclusions can be drawn concerning the movement of the block from the information given.

Explanation / Answer

frictional force Ff = µs*m*g

Ff = 0.5*50*9.8 = 245 N

applied force F = 240 N

applied force is less than the frictional force

F < Ff

so The block remains at rest

Ans => A

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