A +6.00 C point charge is moving at a constant 7.00 ×10^6m/s in the +y-direction

Question

A +6.00 C point charge is moving at a constant 7.00 ×10^6m/s in the +y-direction, relative to a reference frame. At the instant when the point charge is at the origin of this reference frame, what is the magnetic-field vector B it produces at the following points.

Part A

x=0.500m,y=0, z=0

Enter your answers component-wise and numerically separated by commas.

Bx, By, Bz =

Part B

x=0, y=0.500m, z=0

Enter your answers component-wise and numerically separated by commas.

Part C

x=0, y=0, z=+0.500m

Enter your answers component-wise and numerically separated by commas.

Part D

x=0, y=0.500m, z=+0.500m

Enter your answers component-wise and numerically separated by commas.

Bx, By, Bz =

Part B

x=0, y=0.500m, z=0

Enter your answers component-wise and numerically separated by commas.

Part C

x=0, y=0, z=+0.500m

Enter your answers component-wise and numerically separated by commas.

Explanation / Answer

magnetic field due to a moving point charge

B = (uo*q/4pi*r^2)*(vxr)

part(A)

v = 7*10^6 j

r = 0.5i

B = (4*pi*10^-7*6*10^-6/(4*pi*0.5^2))*( 7*10^6 j x 0.5i)

B = 2.4*10^-12*3.5*10^6 (-k)

B = -8.4*10^-6 K

Bx , By , Bz = 0 , 0 , -8.4*10^-6 T

--------------

part(B)

v = 7*10^6 j

r = -0.5j

B = (4*pi*10^-7*6*10^-6/(4*pi*0.5^2))*( 7*10^6 j x -0.5j)

B = 2.4*10^-12*0

B = 0

Bx , By , Bz = 0 , 0 , 0

---------------------

part(C)

v = 7*10^6 j

r = 0.5k

B = (4*pi*10^-7*6*10^-6/(4*pi*0.5^2))*( 7*10^6 j x 0.5k)

B = 2.4*10^-12*3.5*10^6 (i)

B = -8.4*10^-6 i

Bx , By , Bz = 0 , 0 , 0

------------------------

part(D)

v = 7*10^6 j

r = -0.5j + 0.5 k

magnitude of r = sqrt(0.5^2+0.5^2)

B = (4*pi*10^-7*6*10^-6/(4*pi*0.71^2))*( 7*10^6 j x (-0.5j + 0.5 k))

B = 2.4*10^-12*3.5*10^6 i

B = 4.2*10^-6 i

Bx , By , Bz = 4.2*10^-6 , 0 , 0

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