solve the following RC questions A souF is connected in series to a 60n resistor
ID: 1551674 • Letter: S
Question
solve the following RC questions
Explanation / Answer
time constant is T = R*C = 60*50*10^-6 = 3*10^-3 sec
a) voltage across capacitor at t sec is
v = V*(1-e^(-t/T))
given that V = 12 V
t = 2.5 ms = 2.5*10^-3 sec
T = 3 ms
then
v = 12*(1-e^(-2.5/3))
v = 6.78 volt
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b) maximum charge is Q = C*V = 50*10^-6*12 = 600*10^-6 C = 600 uC
C) while discharging
q = Qe^(-t/T)
0.65*Q = Q*e^(-t/(3*10^-3))
0.65 = e^(-t/(3*10^-3))
t = 1.29*10^-3 sec = 1.29 milli sec
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