A 0.33-kg stone is held 1.2 m above the top edge of a water well and then droppe

Question

A 0.33-kg stone is held 1.2 m above the top edge of a water well and then dropped into it. The well has a depth of 5.4 m. (a) Taking y = 0 at the top edge of the well, what is the gravitational potential energy of the stone–Earth system before the stone is released? J (b) Taking y = 0 at the top edge of the well, what is the gravitational potential energy of the stone–Earth system when it reaches the bottom of the well? J (c) What is the change in gravitational potential energy of the system from release to reaching the bottom of the well? J

Explanation / Answer

a) E1 = 0.33*9.81*1.2
= 3.88 J

b) E2 = 0.33*9.81*(-5.4)
= -17.48 J

c) Change = E2 - E1
= -17.48 - 3.88
= 21.36 J

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