1. (Similar to Problem 15, Ch. 21) A charged particle leaves a potential differe

Question

1. (Similar to Problem 15, Ch. 21) A charged particle leaves a potential difference with a speed of 1200 m/s and is headed East. The particle then enters a uniform magnetic field directed into the page with magnitude 21.41 T. When the particle enters the uniform field, it undergoes a specific type of motion, of which begins turning the particle toward the south. A) What type of motion does the particle undergo? B) Draw a detailed diagram of the situation and the ensuing motion of the particle. c) If this motion has a radius of 10.68 cm and the magnitude of the charge on the particle is 3.20 HC, determine the mass of the particle. D) Is the charge on the particle positive or negative? How do you know? E) (Extra credit) If the path of the particle were considered a current loop, it would produce a magnetic field of its own. Determine the magnitude and direction of the magnetic field produced by the "current loop," at the center of the loop. What is the total magnetic field at the center of the loop, if we superpose the external field and the field produced by the "current loop?"

Explanation / Answer

using

F = q V B

centripetal force F = m V2 / r

equating the above equations

q V B = m V2 / r

m = q B r / V

m = 3.2 X 10-6 X 21.41 X 0.1068 / 1200

m = 6.097 X 10-9 kg

this is using because the right hand rule

here the charge is negative..

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