1. The moon orbits the earth at a distance of 3.85 times 10^8 m. Assume that thi
ID: 1548338 • Letter: 1
Question
1. The moon orbits the earth at a distance of 3.85 times 10^8 m. Assume that this distance is between the centers of the earth and the moon and that the mass of the earth is 5.98 times 10^24 kg. Find the period for the moon's motion around the earth. Express the answer in days. A 0.0296 kg ball is shot from the plunger of a pinball machine. Because of a centripetal force of 0.0485 N, the ball follows a circular arc whose radius is 0.309 m. What is the speed of the ball? A curve of radius 113 m is banked at an angle of 16.8 degree. At what speed can it be negotiated under icy conditions where friction is negligible? Two satellites, A and B, are in different circular orbits about the earth. The orbital speed of satellite A is 6.29 times that of satellite B. Find the ratio of the period of satellite A to that of satellite B.Explanation / Answer
1)Here centrepetal acceleration v^2/r = GM/r^2
v = sqrt(GM/r)
T = 2pir/v = 2pi*sqrt(r^3/GM)
= 2 pi*sqrt(3.85e8^3/(6.67e-11*5.98e24))
= 2376607 s
= 2376607/86400 days
= 27.5 days
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