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what is the correct answer? Print E calculator Periodic Table Question 18 of 20

ID: 1547533 • Letter: W

Question

what is the correct answer?


Print E calculator Periodic Table Question 18 of 20 Incorrect Incorrect X Incorrect Incorrect Map a Sapling Learning macmillan learning A certain box contains 100 particles of an ideal gas. How many times more likely is it to find the particles evenly split between the left and right halves of the box, than to find 90 particles on one side and 10 on the other? Incorrect Number You may have found the inverse ratio of the probability of the lopsided configuration to the 2.89 x 10-15 evenly split configuration.

Explanation / Answer

According to the given problem,

Each particle has two possibilities: either it is on the left hand side or it is on the right hand side.
The probability of having them equally split is

P(50,50) = 100C50 / 2100

where 100C50 is the binomial coefficient.

For the uneven distribution we have

P = 2*100C90 / 2100

where the factor 2 comes in because we could have 90/10 or 10/90 as a division.

So the ratio of probabilities is

100C50 /2*100C90

= 2.914 *1015