An ideal gas is heated while maintaining constant pressure and the mean free pat

Question

An ideal gas is heated while maintaining constant pressure and the mean free path increases, which of the following is the explanation? the gas particles are going slower the volume of the gas is increasing the gas particles beginning moving in a synchronized fashion. like in parallel so they collide so often. Condensation is occurring If the number of gas particles in an ideal gas is doubled without the volume changing, by how much does the mean free path change? Double (x 2) One half (x 1/2) Increase by Squareroot 2 Decrease by 1/Squareroot 2

Explanation / Answer

1) b - The volume of the gas is increasing.

On heating, the kinetic energy and hence speed of the gas particles will increase. Therefore, if mean free path increases, it means that the particles have to travel much more distance between two successive collisions. This necessitates much more space among the particles or there should be an increase in volume.

2) b - One half (× 1/2).

Mean free path is inversely proportional to the number (nV) of gas particles per unit volume. If the total number of gas particles is doubled without changing the volume, the number of gas particles per unit volume also gets doubled. As mean free path and nV are inversely related, the doubling of latter will make the former half.

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