Read the Instructions and each problem carefully. Circle the correct answer choi

Question

Read the Instructions and each problem carefully. Circle the correct answer choice, or fill in the blanks as asked for in the problem. If no correct answer is shown in the multiple-choice problems, you should give your answer in (f). Numbers in the [] symbols represent the number of points for that problems Use the figure at the right for problems 1 - 3. For the circuit consisting of air filled, parallel plate capacitors, C_1 - 4.36 mu F, C_2 - 6.72 mu F, C_3 - 7.76 mu F, C_4 - 8.50 mu F, C_5 - 9.50 mu F and C_6 - 12.5 mu F, connected as shown at the right. Determine the equivalent capacitance between points A and B, Answer: 3.78 mu F. 4.68 mu F. 5.27 mu F. 6.52 mu F. 7.03 mu F. C_2 is now removed from the circuit and a potential of 7.0 volts is applied across it. What charge will be on C_2? Answer: 11.1 mu C, 23.6 mu C, 47.0 mu C, 69.5 mu C, 95.4 mu C, A material of dielectric constant 4.8 is placed so as to completely fill between the plates of capacitor C_4. the new value of the capacitance of C_4 is 36.1 mu F, 52.5 mu F, 60.0 mu F, 72.6 mu F, 91.8 mu F, (f) A insulating material has a dielectric strength of 38 kV/mm. If the thickness of the material is 68.6 mm, what is the maximum potential difference that can be applied across it before it is damaged? Answer: 1.88 MV, 2.11 MV, 2.61 MV, 3.14 MV, 4.22 MV, (f). Circle the correct word/words in the parentheses to complete each sentence. To measure electric current in a device in an electric circuit, an Ammeter must be connected in (series parallel) with the device. A (semiconductor, Superconductor is a material that loses all electrical resistance below a certain temperature referred as the critical temperature. "Doping" refers to a process of adding a (small, large) amount of "impurity" atoms' to a material to change its electric properties. To measure electric potential difference across a device in an electric circuit, a voltmeter must be connected in (series parallel) with the device. If a dielectric material is placed in an electric field, electric dipoles (are formed are destroyed) in the material. A certain solid cylindrical wire has a diameter of 5.55 mm and it is connected in a circuit. the resulting current it is 498 A/m^2. What is the current in it at that time? Answer: 3.94 mA. 9.66 mA. 12.0 mA. 16.5 mA. 26.8 mA. (f) A certain wire has electrical resistivity = 5.56 times 10^-8 (Ohm. m) at room temperature. If its length is 550 m and i ulnar cross section of radius = 0.78 mm, what is its electrical resistance at room temperature? Answer: 8.81 Ohm. 11.5 Ohm. 16.0 Ohm.21.3 Ohm. 28.5 Ohm (f) For the circuit shown, R_1 = 25.6 Ohm, R_2 = 32.8 Ohm, R_3 = 47.5 Ohm, 58.2 Ohm, R_5 = 79.7 Ohm and R_6 = 83.9 Ohm. mine the equivalent resistance between A and B. 11.5 Ohm, 39.7 Ohm, 57.2 Ohm.98.4 Ohm. For the circuit at the right R_1 = 35.0 Ohm R_2 = 45.0 Ohm R_3 = 82.0 Ohm, V and = 4.0 V. Determine the power in resistor R_2. 0.00mW, 2.41mW, 14.3 m W, 38.1mW.

Explanation / Answer

here,

C1 = 4.36 uF , C2 = 6.72 uF

C3 = 7.76 uF , C4 = 8.5 uF

C5 = 9.5 uF , C6 = 12.5 uF

C1 , C2 and C3 are in series , let their equivalent capacitance be C7

1/C7 = 1/C1 + 1/C2 + 1/C3

1/C7 = 1/4.36 + 1/6.72 + 1/7.76

C7 = 1.97 uF

C4 , C5 and C6 are in series , let their equivalent capacitance be C8

1/C8 = 1/C4 + 1/C5 + 1/C6

1/C8 = 1/8.5 + 1/9.5 + 1/12.5

C8 = 3.3 uF

C7 and C8 are in parallel,

their equivalent capacitance , C = C7 + C8 = 3.3 uF + 1.97 uF = 5.27 uF

Related Questions

Navigate

• Browse (All)
• Browse R
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.