As shown below, a square loop of wire of side a move through a uniform magnetic
ID: 1545924 • Letter: A
Question
As shown below, a square loop of wire of side a move through a uniform magnetic field of magnitude B perpendicular to the page at constant velocity V directed to the right. Which statement regarding the electric field induced in the wires is correct for the wires at the left and right sides of the loop? (Be careful of what is being asked here. I am not asking for the direction of current.) the electric field E is directed upwards in both the right and left sides of the loop. the electric field E is directed upwards in the right side and downwards in the left side of the loop. the electric field E is directed upwards in the left side and downwards in the right side of the loop. the electric field E is directed downwards in both the right and left sides of the loop. There is no electric field present in any side of the loop.Explanation / Answer
as per dot and cross notation , I am considering the magnetic field is coming out of the page perpendicular to the surface.
firstly in each side of loop as per magnetic force F = q(VxB) we get the direction of force and we get that positive charge is accumulated at bottom and negative charge at top
later as charges get accumulated an electric field is set from positive charge to negative charge and a force is applied as F = qE which is in opposite direction to that of magnetic field
at equilibrium Fe = Fm ie., qE = q(VxB) ; E = VxB
according to this we get the direction of Electrical field as from bottom to top ie., upwards in both sides
option A
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