A coil has N turns enclosing an area of A. In a physics laboratory experiment, t

Question

A coil has N turns enclosing an area of A. In a physics laboratory experiment, the coil is rotated curing the time interval Delta t from a position in which the plane of each turn is perpendicular to earth's magnetic field to one in which the plane of each turn is parallel to the field. The magnitude of Earth's magnetic field at the lab location is B. What is the magnitude Phi_initial of the magnetic flux through the coil before it is rotated? |Phi_initial| = T.m^2 What is the magnitude Phi_final of the magnetic flux through the coil after it is rotated? |Phi_final| = T.m^2

Explanation / Answer

Phi = BAsin(theta)

total magnitude Phi_initial of the magnetic flux through the coil before it is rotated
A.> Phi(i) = BA

the magnitude Phi_final of the total magnetic flux through the coil after it is rotated
B>. Phi(f) = 0

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