1) consider two masses, m1 and m2, with m2=2m1. both masses ae pushed a distance

Question

1) consider two masses, m1 and m2, with m2=2m1. both masses ae pushed a distance d by th same constant foce F.

a) is the work done by the force F in case (m1) greater than, less than or equal to the work done by the force in case (m2)? check our choice and explain your reasoning.

b) is the change in kinetic energey of m1 greate than, less than, or equal to the change in kinetic energy of m2? check your choice and explain your reasoning.

c) is th final velcit of m1 greater than, less than or equal to the final velocity of m2? check your choice and explain you reasoning.

Explanation / Answer

given that

A)))) M2=2M1&Force =Mg

now find work done due to M1 is

work done W1=force * displacement.

                 W1 =M1*g*d....(1)

work done due to M2

                 W2=M2*g*d...(M2=2M1)

                  W2=2*M1*g*d

                                         sinceW1=M1*g*d

                   w2=2*W1

so.workdone by M2 is greater than the workdone by M1

B)))) similarlly,,greater mass particle greater kinetic energy.K.E=1/2*M*v^2

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.