An optical ray traveling in air approaches an equilateral glass triangle, as sho

Question

An optical ray traveling in air approaches an equilateral glass triangle, as shown in the picture associated with this prelab (find it as a separate in the folder). of is8 degrees. Using Snell's Law of refraction, of the glass find the exit angle ray from the on the other side. Define the exit angle, like the incidence angle, relative to the normal. Assume the index of refraction is 1.58. Hint: sketch the path the ray will take. You'll have to use snel's Law twice for this problem, and you'll have to use some geomety to figure out 180 from the first refraction is related to the angle going into the second refraction. (Hint the sum of allthe anglesina iiangie is degrees.)

Explanation / Answer

Sin(i) / sin(r) = mu 2 / mu 1

Sinr = mu1/mu 2 * sin(i)

sin(r) = sin(84)/1.58 = 0.6294

r = 39.01 degrees

The other angle of incidence = 60 -r

60 - 39.01 = 20.99

So 1.58* sin(20.99) = sin(i2)

So sin(i2) = 0.56564 = 34.45 degrees

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