M Fwet Homework Help c x Homework 27 Fwd: PHYS 2210 Webais c e secure l https://
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M Fwet Homework Help c x Homework 27 Fwd: PHYS 2210 Webais c e secure l https://www.webassign.net/weblstudent/Assignment-Responsessubmit?dep 15291144 The figure below shows four capacitors with CA a 3.00 uE ce 5.00 ur, co oo and Co 7.oo wF ed across points a and b, which have potential difference Avab 12.0 V, LIHH Cc Co (a) What is the equivalent capacitance of the four capacit Your response is within 10% of the corroct value. This may be due to roundoff error, or you could have a mistake in your ralculation, Carry out all intermediate results to at east four-digit accuracy to minimize (b) what is the charge on each of the four capacitors? Qa Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error c Your response differs from the correct answer by more than 10%. Double check your calculations. C Your response differs from the correct answer by more than 10%. Double check your calculations. c Your response differs from the correct answer by more than 10% Double check your calculati Need Help? O Ask me anythingExplanation / Answer
(a) Cc and Cd are in series, so their equivalent capacitance= C1= (1/8+1/7)^-1 =3.73uF
c1 and Cb are in parallel, their equivalent capacitance= C1b= 3.73+5= 8.73 uF
C1b and Ca are in series, so the total equivalent capacitance= C= (1/8.73 +1/3)^-1
C=2.23 uF = 2.23x10^-6 F
(b) C= 2.23uF and Vab=12 v
so total charge= Q= C Vab
Q=2.23(12)=26.8 uC
Ca=26.8 uC=2.68x10^-5 C.
Va= Qa /Ca= 26.8/3=8.93 V
so the volatge across the parallel part of circuit=12-8.93=3.07 V
so Qb= Cb Vb=5(3.07)=15.34 uF= 1.534x10^-5 C.
Qc=Qd= Vcd (Ccd)=3.07(3.73)=11.46uC= 1.146x10^-5C
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