Suppose both frequencies are changed to frequency f. The listener moves to point

Question

Suppose both frequencies are changed to frequency f. The listener moves to point Q and finds that the he can hardly hear the sound, indicating destructive interference. Let f = 230 Hz and D is not given. How much further is point Q from S_2 than it is from S_3? 0.175 m, 0.746 m, 0.665 m, 0.686 m The listener returns to point P and speaker 2 is turned off. Speaker 1 broadcasts power P isotropically. What is the sound intensity (in W/m^2) that the listener hears? Let P = 5.00 W. 2.76 times 10^-1 3.82 times 10_1, 4.71 times 10^-1 5.46 times 10^_1 How many decibels does this sound level have if the of hearing is 10^-12 W/m^2? 58.8 dB, 86.7 dB 87.4 dB 84.4 dB A candle of height w is located a distance D from a concave spherical mirror of radius R. Let w = 0.035 m, D = 4.60 m and R = 1.80 m. What is the focal length of the mirror? 0.85m, 0.90 m, 0.75 m, 0.80 m How far from the mirror will the image be? 0.988 m, 1.054 m, 1.119 m, 0.923 m How tall will the image be? 0.0085 m, 0.0046 m, 0.0059 m, 0.0072 m The image will be: Real and upright, Real and inverted, Virtual and upright, Virtual and inverted

Explanation / Answer

The position of image is found as

1/P + 1/ Q = 1/ F

To find the position we have to find the focal length

Which is half the radius f =. 9

Therefore, put p = 4.6

Q = 1.12m

The height is found with
M = yi / yo
To find yi , the magnification is needed.

This magnification is
M = - q / p

M =. 24
The height of the image is therefore
Yi = m yo

Yi =. 035 *. 24

Yi =. 0085

Therefore, the image is real and inserted.

All the answers are below.

15. B

16. C

17. A

18. B

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