A metal rod of length 35 cm is placed in a magnetic field of strength 2.8 T. ori

Question

A metal rod of length 35 cm is placed in a magnetic field of strength 2.8 T. oriented perpendicular to the field. Determine the induced emf, in volts, between the ends of the rod when the rod is not moving. Determine the induced emf, in volts, between the ends of the rod when the rod is moving in the direction of its length at a speed of v = 41 cm/s. Determine the induced emf, in volts, between the ends of the rod when the rod is moving at a speed of v = 41 cm/s perpendicular its length and to the magnetic field.

Explanation / Answer

given

L = 35 cm = 0.35 m

B = 2.8 T

a) we know, Induced emf = B*v*L*sin(theta) (here theta is the angle between v and L)

= 0 (since when rod is not in motion, v = 0 )

b) emf = B*v*L*sin(theta)

= 0 (since here theta = 0 degrees)

c) emf = B*v*L*sin(90)

= 2.8*0.41*0.35

= 0.40 Volts

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