questions 10,11, and 12 please. thanks A rod of mass 0.36 kg and radius 0.033 m
ID: 1542887 • Letter: Q
Question
questions 10,11, and 12 please. thanks
A rod of mass 0.36 kg and radius 0.033 m rests on two parralel rails that are 0.14 m apart and longer than 0.66 m. The rod carries a upward current of 62 A and rolls along the rails without slipping. There is a uniform magnetic field of magnitude 0.58 T directed out of the page and perpendicular to the rod and the rails. What is the work done when the rod has moved a distance of 0.99 m? Answer in units of J. If it starts from rest, what is the speed of the rod after moving a distance 0.99 m? Answer in units of m/s. The rod accelerates to the 1. remains stationary. 2. left. 3. right.Explanation / Answer
10 .
L = length of rod = 0.14 m
B = magnetic field = 0.58 T
i = current = 62 A
F = magnetic force on the rod
magnetic force on the rod is given as
F = i B L Sin90
F = 62 x 0.58 x 0.14 = 5.03 N
d = distance moved = 0.99 m
work done is given as
W = F d = 5.03 x 0.99 = 4.98 J
11.
Vo = initial speed = 0 m/s
Vf = final speed
F = force = 5.03 N
m = mass = 0.36 kg
a = acceleration = F/m = 5.03 /0.36 = 13.97 m/s2
using the equation
Vf2 = Vo2 + 2a d
Vf2 = (0)2 + 2 (13.97) (0.99)
Vf = 5.3 m/s
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