Elements that appear in the same column of the periodic table often share simila
ID: 1542737 • Letter: E
Question
Elements that appear in the same column of the periodic table often share similar chemical properties. In the case of the alkaline earth metals, this is troublesome since the body treats calcium (necessary for proper bone growth) and radium (a radioatictive element) as chemically similar, storing both in bone marrow. The radium then bombards nearby bone cells with alpha particles, causing them to ionized crumble isotope Radium poisoning investigations often center on the identification of radium and its isotopes in bone samples using a mass spectrometer. Pictured is a schematic of a simplified mass spectrometer, showing the paths of calcium, barium (another alkaline earth metal) and radium isotopes entering the chamber. The region shown is immersed in a AV constant magnetic field of 0.352 T pointing out of the plane of the schematic. Motion of the positively-charged isotopes toward the right was initiated by a potential difference of 2361 V on the two plates shown. detector Using the data shown in the table below, calculate the path radius of the Ca ion Number (Scroll down for table and more questions) m Tools Using the s x 10 e, match the particles to their path label.Explanation / Answer
In electric field
W = dV*q
from work energy theorem
Work = dKE = (1/2)*m*v^2 - 0
dV*q = (1/2)*m*v^2
v = sqrt(2*dV*q/m)
In magnetic field
magnetic force provides necessary centripetal force
Fc = Fb
m*v^2/r = q*v*B
r = mv/(qB)
r = (m/(qB))*sqrt(2*dV*q/m)
r = sqrt(2*dV*m/(qB^2)
r = radius
m = mass of the particle
q = charge
B = magneitc field
---------------
r = sqrt(2*dV*m/(qB^2)
for ca+
r = sqrt(2*2361*0.666*10^-25/(1.602*10^-19*0.352))
r = 0.0747 m <<<<------answer
===============================
for ca2+
r = sqrt(2*2361*0.666*10^-25/(3.204*10^-19*0.352))
r = 0.0528 m
for Ba+
r = sqrt(2*2361*2.28*10^-25/(1.602*10^-19*0.352))
r = 0.138 m
for Ba2+
r = sqrt(2*2361*2.28*10^-25/(3.204*10^-19*0.352))
r = 0.098 m
for Ra+
r = sqrt(2*2361*3.75*10^-25/(1.602*10^-19*0.352))
r = 0.177 m
for Ra2+
r = sqrt(2*2361*3.75*10^-25/(3.204*10^-19*0.352))
r = 0.125
for Ra3+
r = sqrt(2*2361*3.75*10^-25/(4.806*10^-19*0.352))
r = 0.102 m
ca+ = 0.074 Ca2+ = 0.0528 m Ba+ = 0.138 Ba2+ = 0.098 m Ra+ = 0.177 m Ra2+ = 0.125 m Ra3+ = 0.102 m
pathA ---- Ca2+
path B ---- ca+
path C ---- Ba2+
path D ---- Ra3+
path E----Ra2+
path F --- Ba+
Path G -- Ra+
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