A gas with an initial temperature of 900 degree C undergoes the process shown in
ID: 1542606 • Letter: A
Question
A gas with an initial temperature of 900 degree C undergoes the process shown in the figure. What type of process is this? adiabatic isochoric isothermal isobaric none of these What is the final temperature in degree C? 118 317 1,000 453 none of these How many moles of gas are there? 1.2 times 10^-3 6.2 times 10^-3 4.8 times 10^-3 3.5 times 10^-3 none of these The amount of work done in the process is 0 J -6.0 times 10^4 J 4.1 times 10^4 J 2.1 times 10^4 J none of these A mole of oxygen (O_2) molecules and a mole of carbon dioxide (CO_2) molecules at the same temperature and pressure have the same average molecular speeds. the same number of atoms. different average kinetic energy per molecule. the same number of molecules. different volumes. At 50.0 degree C, the average translational kinetic energy of a gas molecule is K. If the temperature is now increased to 100.0 degree C, the average translational kinetic energy of a molecule will be approximately 1.07K. 1.15K. 1.41K. 2.00 K. 4.00K Phase changes occur as the temperature decreases as the temperature remains the same as the temperature increases all of these are possible If 40 kcal of heat is added to 2.0 kg of water, what is the change in temperature (in degree C)? 0.05 20 40 80 none of these During an isothermal process, 200 J of heat is removed from an ideal gas. How much work does the gas do during this process? 0J 200 J 100 J -200J 400JExplanation / Answer
1 )
it is an Isobaric Process
Option " D " is correct
2 )
Vi / Vf = Ti / Tf
300 / 100 = ( 900 + 273 ) / T
T = 391 K
T = 391 - 273 = 118 oC
Option " A " is correct
3 )
the gas equation is
PV = n R T
2 X 101325 X 300 X 10-6 = n X 8.314 X ( 900 + 273 )
n = 6.23 X 10-3 mole
Option " B " is correct
4 )
work done W = P dV
W = 2 X 101325 X ( 300 - 100 ) X 10-6
Option " C " is correct
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