A 0.46m copper rod with a mass of 0.19 kg carries a current of 11 A in the posit
ID: 1542588 • Letter: A
Question
A 0.46m copper rod with a mass of 0.19 kg carries a current of 11 A in the positive x direction. Let upward be the positive y direction. What is the magnitude of the minimum magnetic field needed to levitate the rod ?What is the direction of the minimum magnetic field needed to levitate the rod ? A 0.46m copper rod with a mass of 0.19 kg carries a current of 11 A in the positive x direction. Let upward be the positive y direction. What is the magnitude of the minimum magnetic field needed to levitate the rod ?
What is the direction of the minimum magnetic field needed to levitate the rod ? What is the magnitude of the minimum magnetic field needed to levitate the rod ?
What is the direction of the minimum magnetic field needed to levitate the rod ?
Explanation / Answer
Minimum magnetic force = weight
BiL = mg
B*11 * 0.46 = 0.19*9.8
B = 0.367 T
direction should be out of the page
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