give the formul The heaviest invertebrate is the giant squid, which is estimated

Question

give the formul The heaviest invertebrate is the giant squid, which is estimated to have a weight of about 0.28 tons spread out over its length of 31 feet. What is its weight in newtons? _____ N A football punter accelerates a football from rest to a speed of 12 m/s during the time in which his toe is in contact with the ball (about 0.15 s). If the football has a mass of 0.44 kg, what average force does the punter exert on the ball? _____ N A bag of sugar weighs 3.00 lb on Earth. What would it weigh in newtons on the Moon, where the free-fall acceleration is one that on Earth? _____ N Repeat for Mercury, where g is 0.367 times that on Earth. _____ N Find the mass of the bag of sugar in kilograms at each of the three locations. Earth _____ kg Moon _____ kg Mercury _____ kg A freight train has a mass of 1.3 times 10^7 kg. If the locomotive can exert a constant pull of 8.0 times 10^5 N, how long does it take to increase the speed of the train from rest to 62 km/h? _____ min A76-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 836 N. What is the acceleration of the elevator? _____ m/s upward

Explanation / Answer

Solution:

1) 1 ton = 1000 kg

so 0.28 tons =0.28 * 1000 =280 kg

weight = 280 x 9.8 = 2744 N

2) The average force exerted by the punter is calculated from Impulse equation.

Ft = m(vf-vi)

F = m(vf-vi) / t = 0.44(12-0) / (0.15)

= 35.2 N

3) 1 pound force = 4.4 N

3 lb force = 3 x 4.4 = 13.2 N

mass = 13.2 / 9.8 = 1.35 kg

weight on moon = mg = (1.35)(1/6*9.8) =2.21 N on Moon

weight on Mercury = (1.35)(0.367 * 9.8) = 4.86 N on mercury

Weight changes from place to place . But mass is change less whatever mass is on earth , it is same everywhere.

mass on earth = 1.35 kg

mass on moon = 1.35 kg

mass on mercury = 1.35 kg

4) m =1.3 x10^7 kg

F =8 x 10^5 N

It starts from rest ; so vi = 0 and final velocity = 62 kmph = 17.2 m/s

Impulse is defined as the product of force and time .

F t = m(vf-vi)

=> t = m(vf-vi)/F = (1.3 x 10^7) (17.2 - 0 ) / ( 8 x10^5 )

= 2.8 x10^2 seconds = 4.7 minutes

5) mass of the person = m = 76kg

As the elevator rises, a person experiences an increase in weight .

m(g+a) = Fn

=> a = Fn /m -g = 836 / 76 -9.8 = 11 -9.8 =1.2 m/s2

Related Questions

Navigate

• Browse (All)
• Browse G
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.