e l httpslledugenwileyplus.com/edugen/student/mainfruni Halliday, Fundamentals o

Question

e l httpslledugenwileyplus.com/edugen/student/mainfruni Halliday, Fundamentals of physics, 10e introductory physics (Pmms 130a, 1304, 13 ORION Chapter 05, Problem 064 Your answer is partially correct. Try again. The foure shows a box of mass m. 1.1 kg on a frictionless plane incined at angle e 29. sconnected a crrd nedgtie masstoaboe mass 28 koon frictionless and massless. (a) If the magnitude of the horizontal force f is 2.6 r, what is the tension in the connecting cord (b) what isthelaonst value the magnitude of F may have thout the connecting cord (a) Number "umbei unit (b) of s used

Explanation / Answer

m1 = 2.8 kg ; m2 = 1.1 kg ; theta = 29 deg

a)F = 2.6 N

Let T be the tension in the cord.

Sum of forces in X direction:

T + F = m1a (1)

In y direction:

m2g sin(theta) - T = m2a (1)

(1) + (2) will give us:

m2g sin(theta) + F = m1a + m2a

a = [m2g sin(theta) + F]/(m1 + m2)

a = [1.1 x 9.8 x sin29 + 2]/(1.1 + 2.8 ) = 1.85 m/s^2

putting in (1)

T + 2.6 = 2.8 x 1.85 => T = 2.58 N

Hence, T = 2.58 N

b)m2g sin(theta) - T = m2a

m2g sin(theta) - 0 = m2a

a = g sin(theta) = 9.8 x sin29 = 4.75 m/s^2

F = m1a

F = 2.8 x 4.75 = 13.3 N

Hence, F = 13.3 N

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