Thank you 2.0 A 36 ha (36 x 10t m2) mixed residential-industrial land area is ch

Question

Thank you 2.0 A 36 ha (36 x 10t m2) mixed residential-industrial land area is characterized by the following development density 22% multi-unit residential, attached 20 % light industrial 10% neighborhood business 22% parkland 9% paved (asphalt) road surfaces 6% playground 11% unimproved (undeveloped) land (A) A high intensity storm delivers 15 mm of rain over a 3 hour period to this area. Using the Rational Method, determine the peak runoff rate for this storm, and express your answer in m/ second Note that you must first determine a site-specific runoff coefficient for the study area, and convert both the rainfall intensity and the land area to the appropriate values before calculating your answers. A table of various runoff coefficients is attached (B) What would be the peak runoff rate from a low intensity storm over the same area? The storm delivers 4 mm of rain over a 2 hour period. Express your answer in m2 second.

Explanation / Answer

peak runnoff rate= CiA,

where A = Drainage area

C=runoff Coeficient.

i= Strom intensity.(15mm/hr= 4.16 × 10-6 m/s)

q1( multi units residential, attached)=0.70*4.16 × 10-6 *79200 =.23 m3/s

q2(light industrial) =.65*4.16 × 10-6 *72000= 0.19 m3/s

q3(neighborhood buisness) =0.60*4.16 × 10-6 *36000 = .08m3/s

q4(parkland)=0.175*4.16 × 10-6 *79200=0.05m3/s

q5(asphalt road) =0.825*4.16 × 10-6 *32400 =0.11m3/s

q6(playground)= 0.275*4.16 × 10-6 * 21600 =0.02m/s3

q7(underdeveloped land)= .175*4.16 × 10-6 *39600 =0.028m3/s

B) here the rainfall intensity is 4mm/2hr or 2mm/hr =5.56 × 10-7 meter per second(i)

C=runoff Coeficient is same for all cases

A= area is aslo same

so peak runoff rate can be calculated as above

q1( multi units residential, attached)=0.70*5.56 × 10-7*79200 =0.03m3/s

q2(light industrial) =.65*5.56 × 10-7*72000=0.02m3/s

q3(neighborhood buisness) =0.60*5.56 × 10-7*36000 = 0.012m3/s

q4(parkland)=0.175*5.56 × 10-7*79200=7.7*10-03 m3/s

q5(asphalt road) =0.825*5.56 × 10-7*32400 =0.014m3/s

q6(playground)= 0.275*5.56 × 10-7 * 21600 =3.30*10-03m3/s

q7(underdeveloped land)= .175*5.56 × 10-7 *39600 =3.85*10-03m3/s

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.