An object 1.50 cm high is placed 1.50 cm in front of a lens of focal length 4.10

Question

An object 1.50 cm high is placed 1.50 cm in front of a lens of focal length 4.10 cm.
(a) Calculate the image distance with THREE SIG FIGS.
____________cm.
(b) The image is  ---Select--- virtual. real.
(c) The image is located  ---Select--- behind the lens. in front of the lens.
(d) Calculate the magnification, m with THREE SIG FIGS.
_____________
(e) Calculate the image height, where the height can be positive or negative depending on the image's orientation (THREE SIG FIGS).
_______________ cm
(f) The image is  ---Select--- inverted. upright.

Explanation / Answer

Given

   object distance s = 1.5 cm, size of the object y = 1.5 cm

   focal length of the lens is f = 4.10 cm

from the relation 1/s+1/s' = 1/f

where s' is image distance

       1/s' = 1/f - 1/s

           = 1/4.10 -1/1.5

solving for s' , s' = -2.3654 cm ,

b) image is virtual image , enlarges image

c) image is located infront of the lens

d)
magnification m = -s'/s = -(-2.3654/1.5) = 1.57693

the magnification is m = y'/y

e) image height y' is
       y' = m*y
       y' = 1.57693*1.5

       y' = 2.3654 cm

f)the image is upright

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