A boy throws a stone horizontally from the top of a cliff of height h toward the
ID: 1539258 • Letter: A
Question
A boy throws a stone horizontally from the top of a cliff of height h toward the ocean below. The stone strikes the ocean at distance d from the base of the cliff. In terms of h, d, and g, find expressions for the following.
(a) the time t at which the stone lands in the ocean
t =
(b) the initial speed of the stone
vxi =
(c) the speed of the stone immediately before it reaches the ocean
vf =
(d) the direction of the stone's velocity immediately before it reaches the ocean
f = below the horizontal
Explanation / Answer
apply from kinemtice equations of a projectile motion
h = ut + 0.5 gt^2
gt^2 = h
t = sqrt(2h/g)
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b) initial speed vxi = distance /time
Vxi =d * sqrt(g/(2h))
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c) Vertical final speed vy = sqrt(2gh)
v = sqrt(Vxi^2 + Vy^2)
v = sqrt(d^2g/(2h) + 2gh]
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part D:
d) tan-1(vy/vxi)
theta = tan-1(2h/d)
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