Problem 9 LON-CAPA The Learning x C Chegg Study IGuided Sc x CO Sécurisé l https

Question

Problem 9

LON-CAPA The Learning x C Chegg Study IGuided Sc x CO Sécurisé l https //capa.mcgiil.ca/uploaded/mogilw4c20042e9695458bamogill2/default 48657 6066page To avoid electrical fues. wnrings must be sufficiently thick. What should be the diameter of a Cu wire ifit 15 to camy a maximum current of 9.0 A and produce no more than 2.0 Wofheat per meter of length? 9.42x10-4 m Due in 17 hours, 55 minutes You are correct. Computers answer now shown above. p. Your receipt is 157-4788 t La Problem 9 Consider the circuit shown below: RI 570.2 R2 530. S2R. 420.2 R. 840.2 9.00 V a) Calculate the potential difference across R Tries 0/6 Submit Answer b) Calculate the power dissipated in Rs. Submit Answer Tries 0/6 Due in 7 hours. 55 minutes Problem 10 Find the equivalent resistance of the circu as shown in the diagram below: where R -lohn. R2 3 ohn. R 4 ohm, R4 ohm, R. 4 ohm, R6 4 ohm. and R 3 obm. A ETH ENG

Explanation / Answer

9)

Req = R1*R2/(R1+R2) + R3 + R4

= 570*530/(570 + 530) + 420 + 840

= 1524 ohms

Current through battery,R3 and R4 I = V/Req

= 9/1524

= 0.0058646 A

a) V4 = I*R4

= 0.0058646*840

= 4.93 Volts

b) V3 = I*R3

= 0.0058646*420

= 2.46 Volts

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