Will burns a 0.7 g nut beneath 56 g of water, which increases in temperature fro

Question

Will burns a 0.7 g nut beneath 56 g of water, which increases in temperature from 22° C to 50° C.

(a) Assuming 35% efficiency, what is the food value in calories of the nut?
cal

(b) What is the food value in calories per gram?
calories/g

2.If you were caught in freezing weather with only your own body heat for a heat source, would you be warmer in an igloo or in a wooden shack?

igloo or wooden shack    

3. A friend says that in a mixture of gas in thermal equilibrium that the molecules have the same average kinetic energy. Do you agree or disagree?

agree or disagree    

4. Is it important to convert temperatures to the Kelvin scale when we use Newton's law of cooling? Yes or No  

–/0

Explanation / Answer

As we know that

You have to solve this backwards
in order to heat 56g of water from 22 to 50 you will need
56g*(50-22)c * 1cal/g c=1568 cal . If only 35% of energy was used then generated energy is 1568/0.35=4480 cal
So the nut had 4480 cal of energy, which gives 4480/0.7=6400 cal/g

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