A 1.00 kilogram object goes through to two-phase motion. In Phase One, it starts
ID: 1537984 • Letter: A
Question
A 1.00 kilogram object goes through to two-phase motion. In Phase One, it starts from rest on a frictionless Surface when you push on it with a force of 3.00 Newtons for 2.00 seconds. In Phase 2, you can can you to push with the same Force but now there is a friction force that pushes in the opposite direction. With this friction Force, the object continues to move forward for an additional 22.5 meters where it has a velocity of 9.00 m/s. Find the acceleration during each phase and the magnitude of the friction force in Phase 2.
Explanation / Answer
1st phase,
A1=F1/m = 3.00/1.00 = 3.00 m/s^2
2nd phase,
By Kinematic eqn,
vf^2=vi^2+2*a*d
9.0^2 = 0^2 +2*a*22.5
a2= 1.8 m/s^2
Fnet = m*a2 = 1.00*1.8 = 1.8 N
Fnet = F2 - Ff
Ff = F2 – Fnet
Plugging values,
Ff = 3.00 – 1.8 = 1.2 N
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