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The Expert TAIHuman-i x CA Hollow Non-conductin x Secure h ps://usq45tx heexpertta.co /Take Tu alAssignment..aspx Class Management Help Self Assessment Quiz #i Begin Date: 31/2017 12:01:00 AM Due Date: 2/25/2017 11:59:00 PM End Date: 2/25/2017 11:59:00 PM (20%) Problem l Four charges, two positive charges on the x-axis and two negative y-axi charges on the y-axis sit at a distance a 75 cm from the origin. Another positive point charge with charge 9 120 C is located at point P on the x-axis a distance b 1.1 m to the right of this arrangement The positive and negative charges have charge of q -6 uC and -6 LLC respectively. Assignment Status Otheexpertta.com Click here for 25% Part (a) Write an expression for the component of the force in the on on the point charge at P due to the negative charges. detailed view 25% Part b) Write an expression for the x-component of the force on the point charge due to the nearest positive charge Grade Summary Deductions Problem Status Potential 96% Partial Subr a b d 4 5 6 Attempts remaining per attempt Partial detailed view Partial BACKSPACE DEL CLEAR Hints: deduction per hint. Hints remaining Feedback: 2 deduction per feedback. 25% Part (c) Write an expression for the component of the force on the point charge due to the farthest positive charge 25% Part (d) Calculate the total force (n in the x-direction on the point charge Ask me anything 8:19 PMExplanation / Answer
(A) Force due to negative charge will be equal.
magnitude of force due to 1 charge, F = k Q q / (a^2 + (a + b)^2)
cos(theta) = (a + b) / sqrt[ a^2 + (a + b)^2]
Fx- = 2 F cos(theta) = 2 k Q q (a +b) / [ a^2 + (a + b)^2 ]^(3/2)
(b) Fx = - k Q q / (a + b)^2
(c) Fx = - k Q q / (2a + b)^2
(D) Fx- = (2 x 9 x 10^9 x 120 x 10^-6 x 6 x 10^-6) (0.075 + 1.1) / (0.075^2 + 1.175^2)
= 9.33 N
due to nearest = (9 x 10^9 x 120 x 10^-6 x 6 x 10^-6) / (1.175^2) = - 4.6935 N
due to farther = (9x 10^9 x 120 x 10^-6 x 6 x 10^-6) / (1.25^2) = - 4.15 N
net force = 9.33 - 4.69 - 4.15 = 0.49 N
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