As part of a physical therapy program following a knee operation, a 10.0-kg obje

Q: As part of a physical therapy program following a knee operation, a 10.0-kg obje

a) at 0 degree , Torque = 0 b) at 30 deg Torque = 10 * 9.81 * 0.38 * sin30 = 18.64 N.m c) at 60 deg Torque = 10 * 9.81 * 0.38 * sin 60 = 32.28 N.m d) at 90 deg Torque = 10 * 9.81 * 0.38 * sin 90 = 37.28 Nm

ID: 1536261 • Letter: A

Question

As part of a physical therapy program following a knee operation, a 10.0-kg object is attached to an ankle, and leg lifts arc done as sketched in the figure. The value of d in the figure is 38 cm. Calculate the magnitude of the torque about the knee due to this weight for each of the following positions: 0 degree N-m (plusminus 2 N-m) 30 degree N-m (plusminus 2 N-m) 60 degree N-m (plusminus 2 N-m) 90 degree N-m (plusminus 2 N-m) Source Serway and Faughn, College Physics. 6th edition. Problem 8.4 The chewing muscle, the masseter, is one of the strongest in the human body. It is

Explanation / Answer

a) at 0 degree , Torque = 0

b) at 30 deg

Torque = 10 * 9.81 * 0.38 * sin30 = 18.64 N.m

c) at 60 deg

Torque = 10 * 9.81 * 0.38 * sin 60 = 32.28 N.m

d) at 90 deg

Torque = 10 * 9.81 * 0.38 * sin 90 = 37.28 Nm

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As part of a physical therapy program following a knee operation, a 10.0-kg obje

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