A particle with charge - 10^-19 C and mass 10^-31 kg experiences an electric fie

Question

A particle with charge - 10^-19 C and mass 10^-31 kg experiences an electric field of 10^9 N/C; see Figure 3. The particle is initially at rest (immobile) and starts at x =0. Circle your answers! What is the potential difference between the plates V_ = V_b - V_a? 2- What is the surface charge density on each plate (if you assume the plates to be infinite)? For this question you will take _0 = 9 times 10^-12. Give the potential difference V_bx = V_b - V(x) for any x between the plate What is the velocity of the electron when it reaches plate B

Explanation / Answer

1. Electric Field= V/dSo, potential difference = E.d= 10^9*5*10^-10=.5V

2. Electric field=sigma/epsilon

So, surface charge density, sigma =E*epsilon=10^9*9*10^-12=.009 C/sq m

3.E=V/x=sigma/epsilon

So, V=sigma*x/epsilon

4. .5mv^2=qV

So, v=sqrt(2qV/m)=10^6 m/sec

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