1. A common cylindrical copper wire used in a lab is 861 m long. Find the radius

Question

1. A common cylindrical copper wire used in a lab is 861 m long. Find the radius (in mm) of a wire necessary to have 1 Ohms of resistance. (The resistivity of copper at room temperature is 1.68×10-8 Ohm × meter). Express the answer (only numerical value) to one decimal place.

2. Using the R-L graph for a long conducting cylindrical wire with the diameter of D = 0.115 +/- 0.0106 mm, calculate the value 108 x , where is the resistivity in ·m, if the value of the slope S=4.108 and the error of the slope S=0.0214. Express the answer (only numerical value) to two decimal places.

3.Calculate the maximum power that can be dissipated through the load resistor RL in a DC circuit with voltage source V=24 V, internal resistance Ro=27 and load resistor RL. Express the answer to one decimal place.

4. Find the Voltage drop (in mV) across an 47.3 m long copper wire with diameter of 1.02 mm and with 58.9 miliAmps of current running through it. (The resistivity of copper at room temperature is 1.68×10-8 Ohm×meter). Round the answer (only numerical value) to the nearest whole number.

DA 1696 D Tue 3:02 PM a E Chrome File Edit View History Bookmarks People Window Help PRELABs 2017spring-T-PH x a Take Test: Prelab: ohm's Law x CY Yahoo Answers RESOLUTI C Secure https:// /webapps/assessment/take/launch.jsp?course assessment ida 800259 1&course; id 34996... myasucourses.asu.edu Save All Answers Close Window Save and Submit QUESTION 1 3 points Save Answer A common cylindrical copper wire used in a lab is 861 m long. Find the radius (in mm) of a wire necessary to have 1 Ohms of resistance (The resistivity of copper at room temperature is 1.68x10-8 ohm x meter. Express the answer (only numerical value to one decimal place. Question Completion Status: QUESTION 2 4 points Save Answer using the R-L graph for a long conducting cylindrical wire with the diameter of D o.115 +/-0.o106 mm, calculate the value 108 x p, where p is the resistivity in SR-m, if the value of the slope S 4.108 and the error of the slope 4S-0.0214. Express the answer (only numerical value to two decimal places. Linear Fitfor. Data Sot IRasistance m (Slope b Y-Intercept noreply@sh Correlation of para...421 RMSE: 0.01323 Length (m) 00% QUESTION 3 nts Save Answer

Explanation / Answer

1.

Given that

Length of the wire(L) =861m

Resistance of the wire (R) =1ohm

The resistivity of the copper wire(p) =1.68*10-8ohm-m

We know that

p =RA/L =R*pi*r2/L

Then r2 =p*L/Pi*R =(1.68*10-8ohm-m)(861m)/3.14*1

=1446.48*10-8/3.14

Then radius of the wire is given by r =Sqrt(1446.48*10-8/3.14) =21.4630*10-4m =2.146mm

4.

Given that

Length of the copper wire(L) =47.3m

Diameter of the wire(d) =1.02mm =1.02*10-3m

The current passing through the coil is (i) =58.9mAmps =58.9*10-3A

The resistivity of the copper wire(p) =1.68*10-8ohm-m

We know that from the Ohm's law

V =I*R------(1)

and

p =RA/L then R =pL/A -----(2) and A =pi(d/2)2

Then from equation (1) and (2) we can write

V =I*p*L/pi(d/2)2  

Now substitute the values V =(58.9*10-3A)(1.68*10-8ohm-m)(47.3)/3.14*(1.02*10-3m/2)2

=4780.4296*10-11/0.8167*10-6

=5853.348*10-5V =58.53mV

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