45% 3:45 PM iPad F edugen wiley plus.com US Cutnell, Physics, 10e GENERAL PHYSIC

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45% 3:45 PM iPad F edugen wiley plus.com US Cutnell, Physics, 10e GENERAL PHYSICS (PHY 130-140) Gradebook ORION Practice Assignment Assignment CES Chapter 19, Problem 41 The drawing shows a uniform electric field that points in the negative y direction; the magnitude of the field is 7400 N/C. Determine the electric potential difference (a) Va VA between points A and B, (b) Vc Ve between points B and C, and (c) VA Vc between points Cand A. 100 cm 80 cm 6.0 cm (a) Number Units (b) Number Units (c) Number Units Click if you would like to show Work for this question QRen Show Work By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor. Question Attempts: o of 4 used SAVE FOR LATER SUBMITANSWER Earn Maximum Points available only if you answer this question correctly in four attempts or less. Copyright 2000-2017 by John Wiley & Sons, Inc. or related companies. All rights reserved Privacy Policy I R 2000:2017 John Wiley.& Sons Inc. All Rights Reserved. A Division of John Wiley Sons Inc. Version 4.22.1.2

Explanation / Answer

part a )

the displacement from A to B is perpendicular to the electric force, so no work is done. Thus the potential difference is 0

Vb-Va = -Wab/q = 0/q = 0 V

part b )

Vc-Vb = -Eds

Since the electric field points in the negative y direction,

E = -7400 N/C

ds = 0.08 m

Vc-Vb = -Eds = -(-7400)*(0.08) = +592 V

part c )

since electric force is conservative force it does not matter which path we take between points A and C to find the potential difference Va-Vc

for Va-Vc = we willl choose path C-B and B-A

Va-Vc = (Va-Vb) + (Vb-Vc)

since Vb-Vc = -(Vc-Vb) = -592 V

and Va-Vb = -(Vb-Va) = 0

Va-Vc = -592 V

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