Exercise 22.24 Charge 2 is distributed uniformly throughout the volume of an ins

Question

Exercise 22.24 Charge 2 is distributed uniformly throughout the volume of an insulating sphere of radius R> 4.00 cm. At a distance of T 8.00 cm from the center of the sphere, the electric field due to the charge distribution has magnitude 940 N/C Part A What is the volume charge density for the sphere? Express your answer to two significant figures and include the appropriate units. ps Value Units Submit My Answers Give Up Part B What is the magnitude of the electric field at a distance of 2.00 Cm from the sphere's center? Express your answer to two significant figures and include the appropriate units. I E. Value Units Submit My Answers Give Up Provide Feedback Continue

Explanation / Answer

volme charge density rho = Q/Volume = Q/((4/3)*pi*R^3)

Electric field at distance r>R , E = Q/(4*pi*e0*r^2) = k*Q/r^2

charge Q = E*r^2/k

Q = 940*0.08^2/(9*10^9)

Q = 6.68*10^-10 C

volume charge density rho = 6.68*10^-10/((4/3)*pi*0.04^3) = 2.5*10^-6 C/m^3

+++++++++++++++++++++++++++++++++=

part B

at distance r < R

charge inside the gaussian sphere of radis r, q = rho*(4/3)*pi*r^3

electric flux = E*4*pi*r^2

from gass law flux = q/e0

E*4*pi*r^2 = rho*(4/3)*pi*r^3/e0

electric field E = k*rho*(4/3)*pi*r

E = (4/3)*k*rho*pi*r

E = (4/3)*9*10^9*2.5*10^-6*pi*0.02

E = 1885 N/C = 1900 <<<---------answer

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