Question Suppose you launch two identical projectiles from an elevated position

Question

Question Suppose you launch two identical projectiles from an elevated position (well above ground level) at the same initial speed, but at different angles. Which one, if either, will have a greater speed at impact on the ground? Requirements Launch angles must be between either 20-70°; the two angles you choose must differ by at least 15° Only use equations from the Two-dimensional motion, constant acceleration section of the PHYS 1200 Equation Sheet, and any trig you need To answer this question, create a specific experiment (choose the elevated position, the projectiles, their launch speed and launch angles), then solve so you can answer the question, using only equations from the Two-dimensional motion, constant acceleration section of the PHYS 1200 Equation Sheet. Write up your solution as described in the information in this folder, and either bring your work to class or submit a single document in PDF, DOC, or DOCX format using the CX1 link above.

-I NEED TO HAVE SET UP

-EXPERIMENT WITH THE ACTUAL CALCULATION

AND NICE CONCLUSION

Explanation / Answer

Let initial speed = v

Launch angle = theta

let height above ground = h

then initial horizontal velocity = v*cos(theta)

initial vertical velocity = v*sin(theta)

if vertical speed when the projectile reach ground level is v1,

then using the formula is

final speed^2 - initial speed^2 = 2*acceleration*distance

v1^2 - [v*sin(theta)]^2 = 2*g*h

v1 = sqrt(v^2*sin^2(theta) + 2*g*h)

so total speed at the ground level on impact

= sqrt(vertical speed^2 + horizontal speed^2)

= sqrt[v^2*cos^2(theta) + v1^2]

= sqrt[v^2*cos^2(theta) + v^2*sin^2(theta) + 2*g*h]

= sqrt(v^2 + 2*g*h)

so the speed on impact does not depend upon launch angle.

Hence, the both will have same speed on ground impact.

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