A uniform electric field of magnitude 3.8×10 5 N/C points in the positive x dire

Question

A uniform electric field of magnitude 3.8×105 N/C points in the positive x direction.

Part A) Find the change in electric potential between the origin and the point (0, 6.0 m). Express your answer using one significant figure. Delta V = ___ V

Part B) Find the change in electric potential between the origin and the point (6.0 m, 0). Express your answer using two significant figures. Delta V = ___ V

Part C) Find the change in electric potential between the origin and the point (6.0 m, 6.0 m). Express your answer using two significant figures. Delta V = ___ V

Explanation / Answer

as electric field is directed along +ve x axis, potential change will only occur along +ve x axis.

change in potential=electric field*distance

part A:

distance along +ve x axis=0

so change in potential 0 V

part B:

change in distance along +ve x axis=6 m

change in potential=3.8*10^5*6= 2280000 volts

in two significant figures, answer=2.3*10^6 volts

part C:

change in distance along +ve x axis=6 m

change in potential=3.8*10^5*6= 2280000 volts

in two significant figures, answer=2.3*10^6 volts

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