A NaCl molecule is a dipole composed of a positively charged Na atom and a negat

Question

A NaCl molecule is a dipole composed of a positively charged Na atom and a negatively charged Cl atom. Assume that the bond distance in the ground state of this molecule is about 2.8 Angstroms.

1.What is the magnitude of the electric field midway between the Na and Cl atoms? Express your answer in units of MV/m (1x106 V/m).
MV/m

In what direction does the field point at this location?
Correct: toward the Cl atom
Incorrect toward the Na atom
Incorrect none of the above

3.What is the force of attraction between the Na and Cl atoms? Express your answer in units of Newtons and in units of eV/Angstrom.
N
eV/A

Drawing a picture always helps :) And remember, In the SI system the Electric Field is measured in both Newtons/Coulomb(N/C)and Volts/Meter(V/m). 1 N/C = 10-6 MV/m

Explanation / Answer

(a)

electric field is,

e = 2*k*e / (r/2)^2

e = 2*9*10^9*1.6*10^(-19) / (1.4*10^(-10))^2

e = 146938.77 MV/m

(b)

direction = toward the Cl atom.

(c)

F = k*e^2 / r^2

F = 23.5*10^(-9) N

F = 37.61*10^(-38) eV/A

answer

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