A 0.50- F and a 1.4- F capacitor ( C 1 and C 2 , respectively) are connected in

Question

A0.50-F and a1.4-F capacitor (C1 and C2, respectively) are connected in series to a14-Vbattery.

Part A

Calculate the potential difference across each capacitor.

Express your answers using two significant figures separated by a comma.

10, 3.7

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Part B

Calculate the charge on each capasitor.

Express your answers using two significant figures separated by a comma.

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Part C

Calculate the potential difference across each capacitor assuming the two capacitors are in parallel.

Express your answers using two significant figures separated by a comma.

Part D

Calculate the charge on each capasitor assuming the two capacitors are in parallel.

Express your answers using two significant figures separated by a comma.

10, 3.7

Explanation / Answer

Part A : Equivalent capacitance of the capacitors C1 , C2 when they are in series is

Ceq = (C1 C2 ) / (C1 + C2 ) { C1 = 0.50 F , C2 = 1.4 F }

  Ceq = ( 0.50 F x  1.4 F ) / (  0.50 F+1.4 F )

   Ceq = 0.368 F.

The charge on the combined capacitance is Q = Ceq V = ( 0.368 F) (14 V) = 5.152 C

Potential diffrence across C1 is V1 =  Q / C1  = (  5.152 C) / (0.50 F ) = 10.30 V.

Potential diffrence across C2 is V2 =  Q / C2 = (  5.152 C) / (1.4 F ) = 3.68 V

V1 , V2 = 10.30 V , 3.68 V

Part B :

In series connection of the capacitor the caharge on the capacitors would be same and it is equal to the total charge in the circuit,

Q1 = Q2 = Q = 5.152 C

Q1 , Q2 =  5.15 x 10-6 C ,  5.15 x 10-6 C.

Part C: In parallel connection of the capacitors the the voltage diffrence is constant across each capacitors and is equal to the potential difference across the battery.

V1 = V2 = V = 14 V.

V1 , V2 =14.00 V , 14.00 V

Part D :

The equivalent capacitance of the capacitors when they are connected in parallel is

C = C1 + C2 = 0.50 F+1.40 F = 1.90 F.

Charge on the capacitor C1 is Q1 = C1 V = ( 0.50 F) (14 V) = 7.00 C.

Charge on the capacitor C2 is Q2 = C2 V = ( 1.40 F) (14 V) = 19.60 C.

Q1 , Q2 = 7.00 x 10-6 C ,  19.60 x 10-6 C.

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