***The answers selected may not be correct. Please explain each answer. 1. Quest
ID: 1533513 • Letter: #
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***The answers selected may not be correct. Please explain each answer.
1. Question Details My Notes Ask Your Teacher A diatomic molecule can vibrate, the two atoms oscillating back and forth. But by the rules of quantum physics, only very specific oscillations are permitted. For the molecule chosen, there are four possible vibrational states having energies Eg, E1, E2, and E3. The energy separation between any two neighboring states is a fixed quantity . (Greek epsilon) That is En+1 En = , for n = 0, 1, or 2. If this molecule is in thermal equilibrium in a fluid at temperature T, the probability of finding it in an state an energy E above the ground state is: where Po is a normalization factor to guarantee that the probability of everything happening is 1. For simplicity, we write 1. What is the ratio of the probabilities of finding the molecule in its second excited state (E2) compared to that of finding it in its ground state (Eo)? Something else 2. If the temperature increases and the system again reaches equilibrium, the probability of finding the molecule in its second excited state Decreases Remains the same Increases 3. If the temperature increases and the system again reaches equilibrium, the probability of finding the molecule in its ground state Decreases O Is impossible to tell from the information given Increases Remains the sameExplanation / Answer
a) P2/P0 = exp[E1]/exp[E0] = exp[(2 + 1/2)h]/exp[(0 + 1/2)h] = e^2h
b) If the temperature increases and the system again reaches equilibrium, the probability of finding the molecule in its second excited state Increases.
c) Remains same
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