Which of the following increases the speed of waves in a stretched elastic cord?

Question

Which of the following increases the speed of waves in a stretched elastic cord? Increasing the wave amplitude. Increasing the mass density of the cord c) Increasing the driving frequency of the wave. Increasing the tension on the cord. When you increase the driving frequency of a wave on the string, does the wavelength decrease, increase, or stay the same? Decrease Increase Stays the same If we want to find the speed of a wave on the string by varying the frequency Assuming the wavelength is on the y-axis of our linear graph, what do we need to plot on the x-axis so that the slope of the linear graph is v? f 1/f mass F_T For a length of string that is 12.0 m long and has a mass of 32 g, find the linear mass density, mu. 0.0027 kg/m 0.0517 kg/m 2.67 kg/m 19.4 kg/m 375 kg/m If a wave is moving along a string of mass density 15 kg/m at a speed of 10 m/s, what is the tension in the string in Newtons? 0.667 N 1.50 N 6.67 N 150 N 1500 N I set up the experiment as shown in figure 1 of the introduction using a mass of 200 g attached to a string over a pulley to provide tension in the string and measure a wave speed of v. How will the speed of the wave change if I double the mass attached to the string? Find the new speed: a) v/2 v squareroot 2 v 2v 4v Nodes of a standing wave are: Portions of the string that are not vibrating. Portions of the string that have maximum vibration.

Explanation / Answer

1)(d)Increasing the tension in the cord.

because:

v = sqrt (T/mu)

where, T is the tension in the cord and mu is the mass density(m/L)

2)(c)stays the same

because:

lambda = 2L

where L is teh length.

3)(a)f

because:

wavelength is m and speed is m/s. f is s-1 or 1/s

we need f on the x axis to get slope with unit m/s

4)(a)0.0027 kg/m

because:

mu = m/L = 32 x 10^-3 kg/12 = 0.0027 kg/m

5)(e)

because:

v = sqrt (T/mu)

T = v^2 x mu = 100 x 15 = 1500 N

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