(a) Just after the circuit is completed, what is the voltage drop across the cap

Question

(a) Just after the circuit is completed, what is the voltage drop across the capacitor?
V

(b) Just after the circuit is completed, what is the voltage drop across the resistor?
V

(c) Just after the circuit is completed, what is the charge on the capacitor?
C

(d) Just after the circuit is completed, what is the current through the resistor?
A

(e) A long time after the circuit is completed (after many time constants) what are the values of the quantities in parts (a) — (d)?

Explanation / Answer

part a:

when capacitor is initially uncharged, it acts as a short circuit

then voltage drop across capacitor=0 volts

part b:

voltage drop across resistor=E=105 volts

part c:

charge on capacitor=capacitance*voltage=0

part d:

current through resistor=voltage/resistance

=105/7950=0.0132 A

part e:

after a long time, capacitor becomes fully charged and becomes open circuit

so voltage across capacitor=105 volts

voltage drop across resistor=105-105=0 volts

charge on capacitor=4.5*105 uC=472.5 uC

current=0 A

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