A student bikes to school by traveling first dN = 1.00 miles north, then dW = 0.

Question

A student bikes to school by traveling first dN = 1.00 miles north, then dW = 0.500 miles west, and finally dS = 0.100 miles south.

Part A

Take the north direction as the positive y direction and east as positive x. The origin is still where the student starts biking. Let d N be the displacement vector corresponding to the first leg of the student's trip. Express d N in component form.

Express your answer as two numbers separated by a comma (e.g., 1.0,2.0). By convention, the x component is written first.

I need (dN)x,(dN)y = (?,?)

Explanation / Answer

The student first moves in the North direction. Since direction is chosen to be the positive y direction, it is apparent that the motion in this part of the journey is only confined to y direction and thus its x component of displacement will be zero.

therefore, (dN)x = 0 and (dN)y = 1

therefore dN = (0.0, 1.0).

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.