HEY. I NEED YOUR HELP SOLVING THESE TWO PROBLEMS WITH EXPLAINATION AND STEP BY S
ID: 1531406 • Letter: H
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HEY. I NEED YOUR HELP SOLVING THESE TWO PROBLEMS WITH EXPLAINATION AND STEP BY STEP WITH FINAL ANSWER PLEASE. CLEAR HAND WRITTEN PLEASE. THANKS
Question 19 If an electric field of magnitude 25 V/m makes an angle of 30 with a path of length 10 m, then the integral of E dl over this path has a value Not complete Points out of 1.00 Select one: Flag question O A. 217 V. O B. 250 C. 30 D. -250 V E. 125 V. Check Question 20 Four point charges, each of charge 2.5 x 10 C, are located on the x- and y-axes, one at each of the locations (0, 2.0 m), (0, -2.0 m), (2.0 m, 00, and (2.0 m, 0). The potential at the origin is Not Points out of 1,00 Select one: P Flag question A, 4.5 x 10 o B, 3.5 x 10 v O C. 2.3 x 10 D. 1.1 x 10 Check Finish attemptExplanation / Answer
(a)
formula which relates potential difference and electric field is
E = dV/ dl
dV = integral E dl
V = E l cos theta
=25 * 10 cos30
=217 V
(2)
formula potentila due to point charge is
V = kq/r
V total = v1+ v2 + V3 + V4 = 4 kq/r
= 4 (9 10^9) (2.5 * 10^-5 C)/2.0 m
=4.5 * 10^5 V
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