Let q_1 = 3 mu C, Q_2 = 5 Mu C, and Q_3 = -2 Mu C. Find the electric field at th
ID: 1530981 • Letter: L
Question
Let q_1 = 3 mu C, Q_2 = 5 Mu C, and Q_3 = -2 Mu C. Find the electric field at the location of Q_1, due to Q_2 and Q_3. E vector = N/C Use the electric field you calculated in part (a) to find the force on Q_1. F vector = N Find the electric field at location A, due to all three charges. E vector = N/C An alpha particle (He^2+, containing two protons and two neutrons) is released from rest at location A. Use your answer from part (c) determine the initial acceleration of the alpha particle. (Use 6.646 times 10^-27 kg for the mass of He^2+.) a vector = m/s^2Explanation / Answer
a) EF at Q1 due to Q2
= kq2 / r^2 = 9*10^9 * 5*10^-6 / (0.04)^2
= 2812500 N/C
EF due to Q3 = 9*10^9 * 2*10^-6 / (0.05)^2
= 7200000 N /C
Net EF in y - direction = (7200000 * 4/5) - 2812500 = 2947500 N/C
EF in x direction = (7200000*3/5) = 4320000 N/C
EF = sqrt(2947500^2 + 4320000^2) = 5229737 .68 N/C
b) F = q1E
= 3*10^-6 * 5229737.68 = 15.69 N
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