1- A charged object released at point A spontaneously travels to point B. When t

Question

1- A charged object released at point A spontaneously travels to point B. When the object reaches point B is has a non-zero velocity. What can be concluded?

2- For the spherical system to the right, the dielectric constant of the dielectric is = 2. The inner object is a conductor with total charge +Q. The field map of the system is drawn. Is the potential difference along the dashed path positive, negative, or zero?

Friday Homework Problem 5.5 [3 pt(s) jA charged object released at point A spontaneously travels to point B. When the object reaches point Bis has a non-zero velocity. What can be concluded? Select One of the Following: (a) The electric potential must be positive at point A. (b) The electric potential must be positive at point B. (c) There must be a potential difference between the two points. (d) There must be an electric field at both points. (e) There must be no electric field on the path between the two points. Friday Homework Problem 5.6 [3 pt(s) For the spherical system to the right, the dielectric constant of the dielectric is K 2. The inner object is a conductor with total charge +Q. The field map of the system is drawn. Is the potential difference ielectri along the dashed path positive, negative, or zero? air Select One of the Following: (a) positive (b) negative (c) zero

Explanation / Answer

1) Whenever a charged object possesses velocity at other end(B) after travelling from another end(A) then there

must be definitely exists a potential difference between two points.

Since a charge can be moved by doing some work on it which is known as "Electric potential" & we can move

charges between two points with non-zero velocity by creating a potential difference between two points.

Hence (c) is the correct choice.

2) Potential difference along the dashed line is negative.Since,here dashed line represents path against the given

electric field.Hence whenever a charge is moved against the electric field between two points(Potential difference)

the result will be in negative only.

Here path is from di-electric value of k=2 to k=1(for air),hence potential difference will not be zero.

Hence potential difference along dashed line will be negative only.

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