n x M WileyPLUS 4B plc2 E field sum16 pdf Emor: Session Already x C 4B Pk2 E Fie
ID: 1530680 • Letter: N
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n x M WileyPLUS 4B plc2 E field sum16 pdf Emor: Session Already x C 4B Pk2 E Field Sum x G In the figure a emi- X yplus com/edugen/student maintruni C Secure https://edugen.Wileyplus.com/edugen/shared/alertssession conflict uni Apps O Formatting The Java e Complete printf for Ja Gfs Used 2007 Lexus ES 3 D New Tab US Halliday, Fundamentals of Physics, 10e Introductory Physi (PHYS 1303, 1304, 130 Wiley PLUS Assignment Gradebook. ORION ignment oh No! There's a problem here. Chapter 22, Problem 033 Fortunately, it's easy to fix: Just clear your cache and cookies and then try again! In the figure a 'semi-infinite" nonconducting rod (that is, infinite in one direction only) has uniform linear charge To learn how to do this, please click here Clear Your Cache density 4.39 HC/m. Find (including sign) (a) the component of electric field parallel to the rod and (b) the component perpendicular to the rod at point P (R 48.1 m). f WileyPLUS is still not working after trying that, please contact technical support for assistance at rror: Sessien in Progres ethaca e2000 201zughn wlou sens unc. All Rights Res ed. A Divisi of lebn sens unc. 4.22.1.2 Units V (a) Number (b) Number Units Click if you would like to Show Work for this question Open Show Work Question Attempts: 0 of 3 used SAVE FOR LATER SUBMIT ANS Maple Net acy Policy I 2000-2017 Jahn Sana Inc. All Right Reserved. A Division of lohn Wiley Sons Inc. 8:39 PM ENG Type or speak to me 2/9/2017Explanation / Answer
given
lamda = 4.39 micro C/m = 4.39*10^-6 C/m
R = 48.1 m
a)
|Ex| = k*lamda/R
= 9*10^9*4.39*10^-6/48.1
= 821 N/C (towards -x axis)
Ex = -821 N/c
b)
|Ey| = k*lamda/R
= 9*10^9*4.39*10^-6/48.1
= 821 N/C (towards -y axis)
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