can you please answer all the questions which is 006 and 007 ! thanks 006 (part

Question

can you please answer all the questions which is 006 and 007 !
thanks
006 (part 1 of 2) 10.0 points A(n) 71 kg block is pushed along the ceiling with a constant applied force of 930 N that acts at an angle of 69° with the horizontal, as in the figure. The block accelerates to the right at 4 m/s2 The acceleration of gravity is 9.8 m/s2. 71 kg 4 m/s2 What is the magnitude of the normal force the ceiling exerts on the block? Answer in units of N. 007 (part 2 of 2) 10.0 points What is the coefficient of kinetic friction u between the block and the ceiling?

Explanation / Answer

Angle with normal = 90-69 = 21 deg.

Normal force due to the force applied = 930 × cos (21) = 868.23 N. (This is the force ceiling exerts on the body)

Force due to gravity = 71 × 9.8 = 695.8 N

Net normal force = 868.23 - 695.8 = 172.43 N

Net force on the body that makes it accelerate = 71 × 4 = 284 N

Frictional force = 284 - 172.43 = 111.57 N

Coefficient of friction = 111.57 / 172.43 = 0.647.

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.